x+2y+3z=1
2x+2y+4z=2
3x+4y+3z=3
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3x+2y −z = −1. Using the first two equations,. −2x − 2y +3z =5. Add the first two equations. (A) x. +2z =4. This is equation (A), our first equation. −2x −2y +3z = ...3x+2y −z = −1. Using the first two equations,. −2x − 2y +3z =5. Add the first two equations. (A) x. +2z =4. This is equation (A), our first equation. −2x −2y +3z = ...
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The solution of `2x + y + z = 1 , x-2y-3z = 1 , 3x +2y +4z=5` is 1)1,2,3 2) 1,2,-3 3) 1 ...
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"Find the nature of solution for the given system of equation: `x+2y+3z=1;2x+3y+ ...
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`x+2y-3z=-4` `2x+3y+2z=2` `3x-3y-4z=11`
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