Question

(x-2y-3z)^2 if x=1,y=2,z=-1​

Answer 1

Answer:

0

Step-by-step explanation:

(x-2y-3z)^2

putting the values of x, y, z in the above equation

[1-2(2)-3(-1)]^0

[1-4+3]^0

0

Answer 2

Answer:

0

Step-by-step explanation:

Question:-

(x-2y-3z)^2  calculate the value of the equation if,

                           x=1 , y=2 , z=(-1)

Solution:-

substitute the values and you will get the correct answer

=>((1)-(2*2)-(3*-1))^2

=>((1)-(4)-(-3))^2              [You know that minus into minus is plus]

=>(1-4+3)^2

=>(-3+3)^2

=>0

Conclusion:-

the value of the equation (x-2y-3z)^2 is 0 if x=1,y=2,z=(-1)

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