x-2y=4, 3x+5y=1 draw graph
Answers
Answer:
no anwer
Step-by-step explanation:
very hard maths for me
Answer:
-2. 2
Step-by-step explanation:
We have been given pair of equation
x-2y=4x−2y=4 (i) and 3x+5y=13x+5y=1 (ii).
To find the graph,we find the value of x and y from the given equation:
if x=0
\begin{gathered}x-2y=4\\0-2y=4\\y=-2\end{gathered}
x−2y=4
0−2y=4
y=−2
(0,-2)
if x=0,substitute the value in second equation
\begin{gathered}3x-5y=1\\3(0)-5y=1\\y=0.2\end{gathered}
3x−5y=1
3(0)−5y=1
y=0.2
(0,0.2)
Find the value of x and y from equation (i) and (ii) before making the equation same so that we cancel out the same.
Subtract the value of equation (ii) from equation (i)..
\begin{gathered}3x-6y=12\\3x+5y=1\\-11y=11\\y=-1\end{gathered}
3x−6y=12
3x+5y=1
−11y=11
y=−1
Substitute the value of y in equation (i)
\begin{gathered}x-2y=4\\x-2(-1)=4\\x+2=4\\x=2\end{gathered}
x−2y=4
x−2(−1)=4
x+2=4
x=2
(x,y)=(2,-1)
Area of triangle ABC=
\begin{gathered}=\frac{1}{2}[x1(y2-y3)+x2(y3-y1)+x3(y1-y2) ]\\=\frac{1}{2} [2(-2-0.2)+0(0.2+1)+0(-1+2)\\=\frac{1}{2}[2(-2.2)]\\=\frac{1}{2}[-4.4]\\ =-2.2\end{gathered}
=
2
1
[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
=
2
1
[2(−2−0.2)+0(0.2+1)+0(−1+2)
=
2
1
[2(−2.2)]
=
2
1
[−4.4]
=−2.2
Thus,the area of triangle is -2.2−2.2 .
