x+2y=8 and xy=6 find value of (x)3+8(y)3
Answers
Answered by
1
hope this helps.......
Attachments:
Answered by
0
x=8-2y
(8-2y)y= 6
8y-2y^2=6
4y-y^2=3
y^2-4y+3=0
y^2-3y-y+3=0
y(y-3)-1(y-3)=0
y=3 nd y=1
x=8-2(3) nd x=8-2(1)
x=2 nd x= 6
2^3+8(3)^3
8+216
224
(8-2y)y= 6
8y-2y^2=6
4y-y^2=3
y^2-4y+3=0
y^2-3y-y+3=0
y(y-3)-1(y-3)=0
y=3 nd y=1
x=8-2(3) nd x=8-2(1)
x=2 nd x= 6
2^3+8(3)^3
8+216
224
Similar questions