Question

x+2y=8,xy=6,x^3+8y^3

Answer 1

Heya ✋

Let see your answer !!!

$x + 2y = 8 \\ on \: cubing \: both \: sides \\ (x + 2y) ^{3} = (8) ^{3} \\ = > x ^{3} + (2y) ^{3} + 3 \times x \\ \times 2y(x + 2y) = 512\\ = > x ^{3} + 8y ^{3} + 6xy(8) = \\ 512 \\ = > x ^{3} + 8y ^{3} + 6 \times 6 \times 8 \\ = 512 \\ = > x ^{3} + 8y ^{3} + 288 = 512 \\ = > x ^{3} + 8y ^{3} = 512 - 288 \\ = > x ^{3} + 8y ^{3} = 224$




Thanks :)))))