x^2y dx-(x^3+y^3)dy=0
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ANSWER.
= x² y = (x³ + y³) (dy/dx)
= x² y/ (x³ + y³) = 1/((x/y)+(y²/x²)
OR
= dx/dy = (x/y)+(y²/x²)
ΦIntegrating with respect to y, x
= x log y + y³/(3 x²)
ΦThis on simplification will reduce to x³ = y³/3 (1 - log y)
THANKYOU
BEST OF LUCK
CHEERS
FRIEND
THANKYOU YOU ASKING QUESTION.
-------------------------------------------------------
HERE YOUR ANSWER
-------------------------------------------------------
ANSWER.
= x² y = (x³ + y³) (dy/dx)
= x² y/ (x³ + y³) = 1/((x/y)+(y²/x²)
OR
= dx/dy = (x/y)+(y²/x²)
ΦIntegrating with respect to y, x
= x log y + y³/(3 x²)
ΦThis on simplification will reduce to x³ = y³/3 (1 - log y)
THANKYOU
BEST OF LUCK
CHEERS
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