( x - 2y ) ( x^2 + 2xy + 4y^2 )
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Answer:
Expand (x−2y)(x2+2xy+4y2)(x-2y)(x2+2xy+4y2) by multiplying each term in the first expression by each term in the second expression.
x⋅x2+x(2xy)+x(4y2)−2yx2−2y(2xy)−2y(4y2)x⋅x2+x(2xy)+x(4y2)-2yx2-2y(2xy)-2y(4y2)
Simplify terms.
x3−8y3
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(x - 2y) (x² + 2xy + 4y²)
= x (x² + 2xy + 4y²) -2y (x² + 2xy + 4y²)
= x³ + 2x²y + 4xy² -2x²y - 4xy² - 8y³
= x³ - 8y³
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= x (x² + 2xy + 4y²) -2y (x² + 2xy + 4y²)
= x³ + 2x²y + 4xy² -2x²y - 4xy² - 8y³
= x³ - 8y³
Hope it helps you
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