(x^3+1)+(x+1) factorise
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2
→ (x³+1)+(x+1)
={(x)³+(1)³}+(x+1)
=(x+1)(x²-x+1)+(x+1)
=(x+1)(x²-x+1+1)
=(x+1)(x²-x+2).
Answered by
51
Answer:
=(x³+1) +(x+1)
=[{(x) ³+(1)³}+(x+1)}]
={(x+1)(x²+1²-x*1)+(x+1)} [ Since, a³+b³=(a+b) (a²+b²-ab) ]
={(x+1) (x²+1-x)+(x+1) }
=(x+1) (x²+1-x+1) [Taking (x+1) common]
= (x+1)(x²-x+2) {Ans}
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