Question

x=3+2√2 find value of √x-1÷√x​

Answer 1

Answer:

$x = (\sqrt{2} + \sqrt{1} ) {}^{2} \\ \\ \sqrt{x} = \sqrt{2} + 1 \\ 1 \div \sqrt{x } = \sqrt{2} - 1 \\ \sqrt{x} - 1 \div \sqrt{x} = 2$

Answer 2

Answer:

Step-by-step explanation: