x=√3+2 find the value of ( x^2)+(1/x^2)
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(x+1/x)^2=x^2+1/x^2+2
(√3+2+(1/(√3+2))^2-2=x^2+1/x^2
(√3+2-√3+2)^2-2
=16-2=14
ans=14
(√3+2+(1/(√3+2))^2-2=x^2+1/x^2
(√3+2-√3+2)^2-2
=16-2=14
ans=14
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