x=3+2 underrot2 find the value of x^2+1/×^2
Answers
Answered by
0
given x=3+2√2
So x²+1/x²=(3+2√2)²+1/(3+2√2)²
(9+12√2+8)+1/(9+12√2+8)
(9+12√2+8)+1/(17+2√2)
9+12√2+8+17-12√2
=34
The answer is 34.
Anonymous:
no answer is wrong
wrong
How? You've also got the same answer and you're telling me it's wrong
Answered by
0
X= 3 +2 underroot2
=> 1/x = 1/3+2underroot2
= 3 - 2underroot 2 / 3^2 - 2underrot2 ^2
=3 - 2underroot2/1(by rationalising)
Now, x+ 1/x = 3+2root2 + 3 - 2root2
=6
So,
X^2 + 1/x^2 =( x+1/x)^2 - 2 x×1/x
=36- 2=34(ans).hope this helps
=> 1/x = 1/3+2underroot2
= 3 - 2underroot 2 / 3^2 - 2underrot2 ^2
=3 - 2underroot2/1(by rationalising)
Now, x+ 1/x = 3+2root2 + 3 - 2root2
=6
So,
X^2 + 1/x^2 =( x+1/x)^2 - 2 x×1/x
=36- 2=34(ans).hope this helps
good awesome
formula used at last is a^2 + b^2 = (a+b) ^2 - 2ab
thansk season
welcome keep it up and try to answer more questions
thanks a lot mam... means a lot coming from u
now its correct i guess...actually i did not have any rough copy or something in front of me... and i didn't use calculator... i was trying to do it mentally... really sorry for the silly mistake
Similar questions