Question

(x-3)^2 (x-4)^5÷(x-1)^7>0 find fastly please​

Answer 1

( x – 3 )² × ( x –4) ^5

________________ > 0

(x – 1)^7

neglecting ( x – 3 )² as square of no will always be positive.

x – 4 = 0

x = 4

x – 7 = 0

x = 7

x belongs to ( – oo, 4 ) U ( 7 , + 00 ) – { 3 }

Answer 2

Step-by-step explanation:

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