Question

x^3 - 2x - 8 Find zeroes and verify the relationship

Answer 1

Correct Question :-

x^2 - 2x - 8

Solution :-

x ^2 + 4x - 2x - 8

x ( x + 4) + 2 ( x + 4 )

(x + 4) ( x - 2 )

Therefore, zeroes are - 4 & 2

alpha × beta = c/a

(-4)(2) = - 8 / 1

alpha + beta = - b / a

(-4)+(2) = - 2