Math, asked by aryaanurag62033, 7 hours ago

x^3 - 3x +2=0,find the value of x.​

Answers

Answered by kaurpravjot8
1

Answer:

It is easy to see by inspection that

x

=

1

satisfies the equation :

(

1

)

3

3

×

(

1

)

2

=

1

+

3

2

=

0

To find the other roots let us rewrite

x

3

3

x

2

keeping in mind that

x

+

1

is a factor:

x

3

3

x

2

=

x

3

+

x

2

x

2

x

2

x

2

=

x

2

(

x

+

1

)

x

(

x

+

1

)

2

(

x

+

1

)

=

(

x

+

1

)

(

x

2

x

2

)

=

(

x

+

1

)

(

x

2

+

x

2

x

2

)

=

(

x

+

1

)

{

x

(

x

+

1

)

2

(

x

+

1

)

}

=

(

x

+

1

)

2

(

x

2

)

Thus, our equation becomes

(

x

+

1

)

2

(

x

2

)

=

0

which obviously has roots

1

,

1

,

2

We can also see it in the graph:

graph{x^3-3x-2}

Answered by skhatoon9298
0

Answer:

hdjskksk

Step-by-step explanation:

svsiugydtsrsrarstxjv3445×526=10000

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