Question

x^3 + 3x^2 + 3x + 1 /5+2x

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Answer 1

Apply remainder theorem :

=>5+2x =0  

=> 2x = - 5

=> x = - 5/2  

Replace x by � 5/2 we get  

=>x3+3x2 + 3x + 1

=>(-5/2)3 + 3(-5/2)2 + 3(-5/2) + 1

=> -125/8 �+ 75/4 � 15/2 + 1

Add the fraction taking LCM of denominator  

=>(-125 + 150� - 60 + 8 )/125

=> -27/8

Remainder is -27/8