Question

x^3+3x^2-3x+5 by x+2

Answer 1

Solution:-

$\frac{x³+3x²-3x+5 }{x + 2}$

$=> x²+x-5$

Remainder = -5

Answer 2

Step-by-step explanation:

$\huge{\tt{\red{}\green{A}\purple{N}\pink{S}\blue{W}\orange{E}\red{R}}}:)$

$\huge\ \frac{ {x}^{3} + {3x}^{2} - 3x + 5}{x + 2}$

$\huge\ {x}^{2} + x - 5$

= -5