Math, asked by aisha286081, 8 months ago

x^3+3x^2y+3xy^2+y^3-0.008

Answers

Answered by bagkakali

0

Answer:

x^3+3x^2y+3xy^2+y^3-0.008

=(x+y)^3-(0.2)^3

=(x+y-0.2)(x^2+2xy+y^2+.2x+.2y+0.04)

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