Question

X/3+4/4=11 5x/6-y/3=-7

Answer 1

Solution:

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Given:

$\frac{x}{3} + \frac{y}{4} = 11$

Multiplying equation by 12,

We get,

=> $12(\frac{x}{3})+12 ( \frac{y}{4} ) = 11(12)$

=> $4x + 3y = 132$  ...(i)

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$\frac{5x}{6} - \frac{y}{3} = -7$

Multiplying equation by 6,

We get,

=> $6( \frac{5x}{6} ) -6( \frac{y}{3} ) = -7(6)$

=>$5x-2y=-42$ ...(ii)

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To find :

values of x & y,.

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To get value of x, we need to eliminate y,.

This can be done by,.

Adding 3 x (Equation 2) and 2 x (Equation 1)

=> 2(4x + 3y) + 3 (5x - 2y) = 2 (132) + 3 (-42)

=> 8x + 12y + 15x -12y = 264 - 126

=> 23x = 138

=> ∴ x =  6

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Substituting value of x in equation 1,

we get,

=> 4x + 3y = 132

=> 4(6) + 3y = 132

=> 24 + 3y = 132

=> 3y = 132 - 24

=> 3y = 108

=> ∴ y = 36
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                                                     Hope it Helps !!