x^3+4x^2+5 find the derivative
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x−4(3−4x−5)
=3x−4 −4x−5−4
=3x−4−4x−9
Differential of x−4(3−4x−5)=Differential of
=3x−4−4x−9
= dx
d. (3x−4 −4x −9)
= dx
d. (3x−4)−dx
d. (4x−9)
=3 dx
d. (x−4 )−4 dx
d. (x−9 )
=4(−4x−4−1)−4(−9x−9−1 )
=−16x−5+36x−10
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