x^3-6x^2+8x/x-4 find its quotient
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The quotient is x^2 - 2x
Hope it helps :-)
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Step-by-step explanation:
FIRST LETS FACTORISE THE DIVIDEND:
x³-6x²+8x = x( x²-6x+8 )
= x( x²-4x-2x+8 )
= x[ x(x-4)-2(x-4)]
= x(x-4)(x-2)
SEE!!!!! WE HAVE (x-4) AS A FACTOR AND ALSO IT IS THE DIVISOR IN THIS CASE.
SO WE HAVE NO WORRIES LEFT
LETS DIRECTLY DIVIDE AND GET THE ANSWER.
x³-6x²+8x = x(x-4)(x-2) = x(x-2) = x²-2x
(x-4) (x-4)
HENCE THE REQUIRED QUOTIENT IS x²-2x.
ALSO YOU CAN DO THIS BY LONG DIVISION METHOD, BUT THIS IS PRETTY SIMPLE.
PLEASE MARK MY ANSWER AS BRAINLIEST .
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