Question

x+3/7 ‐ 2x‐5/3=3x‐5/5 ‐25​

Answer 1

Step-by-step explanation:

If roots of the quadratic equation \bf 2x^2-6x+3=02x

2

−6x+3=0 are \bf \alpha \:,\:\betaα,β

Then prove that

\Large{\sf \dfrac{\alpha}{\beta}+\dfrac{\beta}{\alpha}+5\left(\dfrac{1}{\alpha}+\dfrac{1}{\beta}\right)+2\alpha\beta=17}

β

α

+

α

β

+5(

α

1

+

β

1

)+2αβ=17