x
3
If the area bounded by y= - x2 +a , x = 0, x = 2 and x-axis is minimum then lind a.
3
Find the area bounded by the inverse of bijective function f (x) = 4x + 6x, the x-axis and the ordinates
x = 0 &x= 44.
nd
2,3
2x The area hounded by or
Answers
Answered by
1
Correct option is
D
8
R.E.F image
f(x)=x+sinx
So area between f(x) & f
−1
(x) is double
the area between f(x)&y=x
Area (A) = ∫
0
2π
(x+sinx)
dx
∫
0
2π
xdx
=∫
0
2π
sinxdx
=∫
0
π
sinxdx−∫
π
2π
sinxdx
=[−cosx]
0
π
−[−cosx]
π
2π
=2+2=4
Actual Area = 2×A=8
Option D is correct.
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