Question

x= (3+ root under 8) ,find the value of ( x^2+1/x^2)
plz explain ​

Answer 1

Step-by-step explanation:

Given that..

x=3+8–√…(1)x=3+8…(1)

⇒1x=3−8√(3)2−(8√)2⇒1x=3−8(3)2−(8)2

⇒1x=3−8–√….(2)⇒1x=3−8….(2)

Now adding (1) & (2) we get…

x+1x=(3+8–√)+(3−8–√)x+1x=(3+8)+(3−8)

⇒x+1x=6⇒x+1x=6

Now,

x2+1x2x2+1x2

=(x+1x)2–2.x1x=(x+1x)2–2.x1x

=62–2=62–2

=36–2=36–2

=34=34. (Ans

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Answer 2

Hey mate,

x=3+3x2=(3+ 8 ) 2 =9+8+68=17+68x2+x21=(3+8 )2+( 3+8 ) 21

⇒17 +618 + 17+681

⇒ 17+6 8(17+6 8 ) 2+1 × (17−68)(17−68 )

⇒ 289−288 (17+6 18 ) 2 (17−6 8 )+(17−6 8 )

⇒(289−288)(17+68 )+17−6 8

⇒17+6 8+17−6 8 =34

Hope it helps.