Question

calculate no. of moles of solute in N/20 400ml of Na2CO3​

Answer 1

Dear Student,

◆ Answer -

Moles of solute = 0.01 mol

● Explanation -

# Given -

Volume of soln = 400 ml = 0.4 L

Normality = N/20 = 1/20 N

# Solution -

For Na2CO3 valence of Na is 2.

Normality is calculated by -

Normality = Valence × molarity

Normality = Valence × moles of solute / volume of solution

Substitute values -

1/20 = 2 × moles of solute / 0.4

Moles of solute = 0.4 / (20 × 2)

Moles of solute = 0.01 mol

Therefore, moles of solute in the solution is 0.01 mol.

Thanks dear...