x+3/x+2+x-2/x-3=5/(x+2)(x-3). factorizing method
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Given equation:
x
4
−3=
2x+3
5
⟹
x
4−3x
=
2x+3
5
⟹(4−3x)(2x+3)=5x
⟹8x+12−6x
2
−9x=5x
⟹−6x
2
−6x−12=0
⟹x
2
−x−2=0
a=1,b=−1,c=−2
D=b
2
−4ac
⟹D=(−1)
2
−4(1)(−2)
⟹D=1+8
⟹D=9
∴ Roots are real and distinct
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