Question

( x-3) (x+3)=16 then x = ?​

Answer 1

Answer:

$(a - b)(a + b) = {a}^{2} - {b}^{2}$

$\: \: \: \: \: \: (x - 3)(x + 3) = 16$

$= > {(x)}^{2} - {(3)}^{2} = 16$

$= > {x}^{2} - 9 = 16$

$= > {x}^{2} = 16 + 9$

$= > {x}^{2} = 25$

$= > x = \sqrt{25}$

$= > x = \sqrt{5 \times 5}$

$= > x = 5$

Answer 2

Answer:

x^2+3x-3x-9=16

x^2-9=16

x^2=16-9

x^2=7

x=root7

Step-by-step explanation:

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