Math, asked by yugank004595, 1 day ago

(x+3)(x-3)(x^2+9) please answer this fast​

Answers

Answered by meet23052007
0

Answer:

4−81

Step-by-step explanation:

(+3)(−3)(2+9)

{\color{#c92786}{(x+3)(x-3)(x^{2}+9)}}(x+3)(x−3)(x2+9)

(2+9)(−3)+3(2+9)(−3)

(2+9)(−3)+3(2+9)(−3)

{\color{#c92786}{x(x^{2}+9)(x-3)}}+3(x^{2}+9)(x-3)x(x2+9)(x−3)+3(x2+9)(x−3)

(−3)3+9(−3)+3(2+9)(−3)

(−3)3+9(−3)+3(2+9)(−3)

{\color{#c92786}{(x-3)x^{3}}}+9x(x-3)+3(x^{2}+9)(x-3)(x−3)x3+9x(x−3)+3(x2+9)(x−3)

4−33+9(−3)+3(2+9)(−3)

4−33+9(−3)+3(2+9)(−3)

x^{4}-3x^{3}+{\color{#c92786}{9x(x-3)}}+3(x^{2}+9)(x-3)x4−3x3+9x(x−3)+3(x2+9)(x−3)

4−33+92−27+3(2+9)(−3)

4−33+92−27+3(2+9)(−3)

x^{4}-3x^{3}+9x^{2}-27x+{\color{#c92786}{3(x^{2}+9)(x-3)}}x4−3x3+9x2−27x+3(x2+9)(x−3)

4−33+92−27+3(−3)2+27(−3

4−33+92−27+3(−3)2+27(−3)

x^{4}-3x^{3}+9x^{2}-27x+{\color{#c92786}{3(x-3)x^{2}}}+27(x-3)x4−3x3+9x2−27x+3(x−3)x2+27(x−3)

4−33+92−27+33−92+27(−3)

x^{4}-3x^{3}+9x^{2}-27x+{\color{#c92786}{3x^{3}-9x^{2}}}+27(x-3)x4−3x3+9x2−27x+3x3−9x2+27(x−3)

4−33+92−27+33−92+27(−3)

x^{4}-3x^{3}+9x^{2}-27x+3x^{3}-9x^{2}+{\color{#c92786}{27(x-3)}}x4−3x3+9x2−27x+3x3−9x2+27(x−3)

4−33+92−27+33−92+27−81

4−33+92−27+33−92+27−81

x^{4}{\color{#c92786}{-3x^{3}}}+9x^{2}-27x+{\color{#c92786}{3x^{3}}}-9x^{2}+27x-81x4−3x3+9x2−27x+3x3−9x2+27x−81

4+92−27−92+27−81

4+92−27−92+27−81

x^{4}+{\color{#c92786}{9x^{2}}}-27x{\color{#c92786}{-9x^{2}}}+27x-81x4+9x2−27x−9x2+27x−81

4−27+27−81

4−27+27−81

x^{4}{\color{#c92786}{-27x}}+{\color{#c92786}{27x}}-81x4−27x+27x−81

4−81

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