(x+3)(x+5)(x+7)=? how to do it?
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first solve first two brackets
then the remaining two
then the remaining two
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Given Equation is (x + 3)(x + 5)(x + 7) --------- (1)
(1) (x + 3)(x + 5)
= x * x + x * 5 + 3 * x + 3 * 5
= x^2 + 5x + 3x + 15
= x^2 + 8x + 15 -------------- (2)
Substitute (2) in (1), we get
Therefore (x+3)(x+5)(x+7) = (x^2 + 8x + 15)(x + 7)
= x^2 * x + x^2 * 7 + 8x * x + 8x * 7 + 15 * x + 15 * 7
= x^3 + 7x^2 + 8x^2 + 56x + 15x + 105
= x^3 + 15x^2 + 7x + 105.
Hope this helps!
(1) (x + 3)(x + 5)
= x * x + x * 5 + 3 * x + 3 * 5
= x^2 + 5x + 3x + 15
= x^2 + 8x + 15 -------------- (2)
Substitute (2) in (1), we get
Therefore (x+3)(x+5)(x+7) = (x^2 + 8x + 15)(x + 7)
= x^2 * x + x^2 * 7 + 8x * x + 8x * 7 + 15 * x + 15 * 7
= x^3 + 7x^2 + 8x^2 + 56x + 15x + 105
= x^3 + 15x^2 + 7x + 105.
Hope this helps!
ROHANDey1:
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