Math, asked by rahul643, 1 year ago

(x+3)(x+7)/(x-5)(x+3)=1


jaya1012: value of x can't exist

Answers

Answered by jaya1012
2
(x+3)(x+7)=(x-5)(x+3)
=
 {x}^{2}  + 10x + 21 =  {x}^{2} - 2x - 15
=12x=-15-21
=12x=-36
x=-36/12
x=-3

:-) hope it helps u.
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