(x+3)(x+7)/(x-5)(x+3)=1
jaya1012:
value of x can't exist
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(x+3)(x+7)=(x-5)(x+3)
=
![{x}^{2} + 10x + 21 = {x}^{2} - 2x - 15 {x}^{2} + 10x + 21 = {x}^{2} - 2x - 15](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B2%7D++%2B+10x+%2B+21+%3D++%7Bx%7D%5E%7B2%7D+-+2x+-+15+)
=12x=-15-21
=12x=-36
x=-36/12
x=-3
:-) hope it helps u.
=
=12x=-15-21
=12x=-36
x=-36/12
x=-3
:-) hope it helps u.
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