Question

X/3+y/2=3, x-2y=2 find X and y if the equations have unique solution​

Answer 1

Answer:

x-2y=2..........(1)

X/3+y/2=3

2x+3y/6=3

2x+3y=18

x=18-3y/2........(2)

put the value of x in equation (1)

therefore

18-3y/2+2y=2

18-3y+4y/2=2

18-y=4

y=18-4

y=16

put value of y in equation (2)

x=18-3(16)/2

x= -30/2

x=-15

hence, x=-15 and. y=16

Answer 2

Answer:

x=6 y=2

Step-by-step explanation:

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