Question

x ^ -3 y ^ -4 * x ^ 3 y ^ 4???​

Answer 1

Answer:

${x}^{ - 3} {y}^{ - 4 } \times {x}^{3} {y}^{4 } \\ combining \: like \: terms \\ we \: get \: \: \: \: \: {x}^{ - 3} {x}^{3} \times {y}^{ - 4} {y}^{4} \\ = {x}^{ - 3 + 3} \times {y}^{ - 4 + 4} \: \: \: by \: law \: of \: indices \\ = {x}^{0} \times {y}^{0} = 1 \times 1 = 1$

anything to the power 0 is equal 1 so x^0 =1 and y^0 =1...

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Answer 2

Answer to Let f(x, y) = (2x, 3y) for all (x, y) R^2. Let A = {(x, y): x^2 + y^2 < 1} Note that A can be described geometrically as...

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