Question

X + 3 Y = 6 and 2 x minus 3 Y equal 12 then find the value of f from the equation for X + 3 Y equal=a​

Answer 1

Answer:

a=6

Step-by-step explanation:

let x+3y=6 be equation 1

2x-3y=12 be equation 2

On adding 1 and 2

(x+3y) + (2x-3y) = 6+12

x+3y + 2x-3y = 6+12

3x=18

x=18/3

x=6

Substitute the value of x in equation 1

x+3y=6. (x=6)

6+3y=6

3y=6-6

3y=0

y=0

Substitute the values x=6 and y=0 in the equation x+3y=a to get the value of a

x+3y=a

6+(3x0)=a

6=a

a=6

Answer 2

$\huge\tt\blue{Answer:-}$

Given, eq. are

${x+3y=6}$________(i)

${2x-3y=12}$ _________(ii)

Adding (i) and (ii)

${x+3y+2x-3y=6+12}$

$\longrightarrow {3x=18}$

$\longrightarrow {x=6}$

Putting the value of x in eq. (i)

${6+3y=6}$

$\longrightarrow {3y=0}$

$\longrightarrow {y=0}$

Again, putting the values of x and y in the given eq.

$\longrightarrow {x+3y=a}$

$\longrightarrow {6+3×0=a}$

$\longrightarrow {a=6}$

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