Math, asked by vamshinenta0307, 3 months ago

x^3dy/dx=y^3+y^2✓y²-x²​

Answers

Answered by muskanot7
1

x \:  =  \frac{3dy}{dx}

= y³+y²√y²-x² = y^5 √y² -  \frac{3dy}{dx}

your answer is y5√y2-3dy/dx

hope this helps you❤️

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