x=3is one root of the quadratic equation x2-2kr-=0 then find the value of k
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Hey.. Actually ur question is incomplete.. But I have read question so answering.. Just check it out!!
Polynomial - x2 - 2kx - 6 =0
P (3) =(3) 2-2(3)k =6
=9 - 6k =6
=-6k =-3
=k =1/2
Polynomial - x2 - 2kx - 6 =0
P (3) =(3) 2-2(3)k =6
=9 - 6k =6
=-6k =-3
=k =1/2
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