find the sum of first five multiples of 3?
Bubu11:
45
Answers
Answered by
141
A=D=3
S5=5/2(2A+4D)
S5=5(A+2D)
S5=5(3+6)
S5=5(9)
S5 = 45
S5=5/2(2A+4D)
S5=5(A+2D)
S5=5(3+6)
S5=5(9)
S5 = 45
Answered by
63
Answer:
45
Step-by-step explanation:
First five multiples of 3 are :
So, the first five multiples of 3 are 3,6,9,12,15
Now the sum of first five multiples of 3 = 3+6+9+12+15 = 45
Hence the sum of first five multiples of 3 is 45
Similar questions