Math, asked by Sara1305, 1 year ago

x=3secA y=4tanA
eliminate A​

Answers

Answered by koyel2232002gmailcom
2

Answer:

sec A=x/3

tanA=y/4

sec^2A+tan^2A=(x^2/9)+(y^2/16)

1=(16x^2+9y^2)/144

16x^2+9y^2=144

Step-by-step explanation:

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