x=3secA y=4tanA
eliminate A
Answers
Answered by
2
Answer:
sec A=x/3
tanA=y/4
sec^2A+tan^2A=(x^2/9)+(y^2/16)
1=(16x^2+9y^2)/144
16x^2+9y^2=144
Step-by-step explanation:
please mark as a brainliest
Similar questions