X=3sin square a,y=3cossquare a+3,find x+y
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From question,
x+y = 3 (sin a)^2 + 3 (cos a)^2+3
= 3[ sin square a + cos square a] + 3
= 3(1) + 3 ( since sin square theta+ cos square theta = 1, identity)
= 6
Hope you have understood.
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