Question

x+3y=5;7x-8y=6 by cross multiplication method ​

Answer 1

$\textbf{Given:}$

$x+3y-5=0\;\text{and}\;7x-8y-6=0$

$\textbf{To find:}$

$\text{Solution by cross multiplication rule}$

$\textbf{Solution:}$

$\text{Consider,}$

$x+3y-5=0$

$7x-8y-6=0$

$\text{By cross multiplication rule,}$

$\dfrac{x}{3(-6)+5(-8)}=\dfrac{y}{7(-5)+6(1)}=\dfrac{1}{1(-8)-3(7)}$

$\dfrac{x}{-18-40}=\dfrac{y}{-35+6}=\dfrac{1}{-8-21}$

$\dfrac{x}{-58}=\dfrac{y}{-29}=\dfrac{1}{-29}$

$\dfrac{x}{-58}=\dfrac{1}{-29}$

$\implies\,x=\dfrac{-58}{-29}$

$\implies\boxed{\bf\,x=2}$

$\text{and}$

$\dfrac{y}{-29}=\dfrac{1}{-29}$

$\implies\,y=\dfrac{-29}{-29}$

$\implies\boxed{\bf\,y=1}$

$\textbf{Answer:}$

$\textbf{Solution is x=2 and y=1}$

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