Question

x+3y=6 , 2x-3y=12 ..Solve it in substitution method.
Ans step by step.
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Answer 1

$from \: equation \: 1 \\ x = 6 - 3y \\ by \: substituting \: the \: value \: of \: x \: in \: equation \: 2 \\ 2(6 - 3y) - 3y = 1 2 \\ 12 - 6y - 3y = 12 \\ 12 - 9y = 12 \\ 12 - 12 = 9y \\ 9y = 0 \\ y = 0 \\ x = 6 - 3(0) \\ x = 6$

Answer 2

Answer:

=> x = $6$ and y = $0$

Step-by-step explanation:

As per the given data, we have to solve the given expression by using the substitution method,

Given equations:-

$x+3y=6$         $...(1)$

$2x-3y=12$     $...(2)$

Now, by adding both the equation we get,

=> $3x = 18$

By dividing 18 by 3, we get

=> $x = 6$

Now, put the value of x in equation (1), we get

=> $6+3y=6$

=> $3y=6-6$

=> $3y=0$

=> $y=0$

Hence by substitution method, the value of x is 6 and y is 0.