Question

x=3y+6 then show that x^3-8y^3-36xy-216​

Answer 1

Given:x=2y+6

So, x-2y-6=0 or x+(-2y)+(-6)=0

If a+b+c=0, then a^3+b^3+c^3=3abc

So, x^3+(-2y)^3+(-6)^3=3(x)(-2y)(-6)

Or, x^3-8y^3-216=36xy

Therefore, x^3-8y^3-36xy-216=0

Hence the answer is 0

Answer 2

Answer:

hola mate.

see the attachment

hope it helps you