Question

SOLVE THIS QUESTION:​

Answer 1

Your Answers = 200 × 10³ Ω

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➡ Welcome to the concept of current and electricity.

➡ Basically we will apply kirchoff's law

Applying Kirchhoff's law to mesh ADCEFA

V(cc) = 10 = I(c) × 10³ + V(CE) =

⇒10 = I(c) × 10³ + 5

⇒I(c) = 5 × 10¯³ A _______(1)

Applying Kirchhoff's law to mesh AGBEFA

I(B) × R(B) + V(BE) = V(cc) = 10 v

⇒I(B) × R(B) + 0 = 10

⇒5 × 10¯⁵ × R(B) = 10______(2)

On solving

R(B) = 200 × 10³ Ω

Hence, answer (3)

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