x-3y-7=0 and 3x-3y-15=0 find cross multiple method
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By cross multiplication method
x-3y-7=0
3x-3y-15=0
x/(-3)(-15)-(-7)(-3)=y/(1)(-15)-(3)(-7)
1/(1)(-3)-(3)(-3)
x/24=y/6=1/6
x/4=y/1=1/1
Therefore x=4 and y=1
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