Question

y=x2^x find derivative​

Answer 1

Answer:

2(1+lnx)x2x

Step-by-step explanation:

Explanation:

We need

(uv)'=u'v+uv'

y=x2x

lny=ln(x2x)

lny=2xlnx

Differentiating wrt x

1ydydx=2(x⋅1x+1⋅lnx)

dydx=2(1+lnx)y

dydx=2(1+lnx)x2x

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