Question

(x+3y)+i(2x-5y)=5i find the value of x and y​

Answer 1

Answer:

15/11 and - 5/11

Step-by-step explanation:

⇒ (x + 3y) + i(2x - 5y) = 5i

⇒ (x + 3y) + i(2x - 5y) = 0 + 5i

      Comparing, real number of RHS = real number on LHS

⇒ x + 3y = 0

⇒ x = - 3y          ...(1)

       Comparing imaginary parts:

⇒ 2x - 5y = 5

⇒ 2(-3y) - 5y = 5     { from (1)}

⇒ - 6y - 5y = 5

⇒ y = - (5/11)

        Hence,

x = - 3(-5/11) = 15/11

Answer 2

Answer:

Step-by-explation:

⇒ (x + 3y) + i(2x - 5y) = 5i

⇒ (x + 3y) + i(2x - 5y) = 0 + 5i

Comparing, real number of RHS = real number on LHS

⇒ x + 3y = 0

⇒ x = - 3y ...(1)

Comparing imaginary parts:

⇒ 2x - 5y = 5

⇒ 2(-3y) - 5y = 5 { from (1)}

⇒ - 6y - 5y = 5

⇒ y = - (5/11)

Hence,

x = - 3(-5/11) = 15/11