x^4-2x^2y^2+y^4 factorise
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x^4+2x^2 y^2+ y^4
= x^4 + x^2 y^2+ x^2 y^2 +4y^2
( taking common )
= x^2( x^2+ y^2) + y^2( x^2+ y^2)
=( x^2+ y^2 ) ( x^2+ y^2)
Hope, it helped
= x^4 + x^2 y^2+ x^2 y^2 +4y^2
( taking common )
= x^2( x^2+ y^2) + y^2( x^2+ y^2)
=( x^2+ y^2 ) ( x^2+ y^2)
Hope, it helped
Answered by
4
Hi there!
Given poly. x⁴ - 2x²y² + y²
Rewrite x⁴ as (x²)² :
(x²)² - 2x²y² + y⁴
Rewrite y⁴ as (y²)² :
(x²)² - 2x²y² + (y²)²
Check the middle term by multiplying 2ab and compare this result with the middle term in the original expression.
2ab = 2 × x² × (−y²)
Simplify.
2ab = −2x²y²
Factor using the perfect square trinomial rule a²−2ab+b² = (a−b)², where a = x² and b = −y²
(x² - y²)²
[ (x + y) (x - y) ] ---[ Factorised. ]
[ Thank you! for asking the question. ]
Hope it helps!
Given poly. x⁴ - 2x²y² + y²
Rewrite x⁴ as (x²)² :
(x²)² - 2x²y² + y⁴
Rewrite y⁴ as (y²)² :
(x²)² - 2x²y² + (y²)²
Check the middle term by multiplying 2ab and compare this result with the middle term in the original expression.
2ab = 2 × x² × (−y²)
Simplify.
2ab = −2x²y²
Factor using the perfect square trinomial rule a²−2ab+b² = (a−b)², where a = x² and b = −y²
(x² - y²)²
[ (x + y) (x - y) ] ---[ Factorised. ]
[ Thank you! for asking the question. ]
Hope it helps!
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