Question

X + 4 equals to zero then find the value of x cube + y cube + 12 x y - 64​

Answer 1

X+4=0

X=-4

${ - 4}^{3} + {y}^{3} + 12 \times - 4 \times y - 64$

$- 64 + {y}^{3} + - 48y - 64$

${y}^{3} + -48y - 128$