x^4+x^2+1 factorise
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Answer:
We have
x4+x2+1=(x2+1)2–2x2+x2=(x2+1)2−x2
=(x2+1−x)(x2+1+x) (of the form A2−B2 )
And in C
x4+x2+1=(−x+ω−1)(ω−x)(x+ω−1)(x+ω)
where ω=eiπ/3
or
most simply it can be factorised as
x^4+x^2+1 = (x^2+1)^2 - (x^2)
= (x^2+x+1) - (x^2-x +1)
hope this helps you
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