Question

(x+4)(x+3)-(x-4)(x-3) is equal to

(a)
$2 {x}^{2} - 14x \: + 24$
(b)
$2{x }^{2} + 14x - 24$
(c)
14x

(d)
24

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Answer 1

$(x + 4)(x + 3) - (x - 4)(x - 3) \\ = ({x}^{2} + 3x + 4x + 12) - ( {x}^{2} - 3x - 4x + 12) \\ = {x}^{2} + 7x + 12 - {x}^{2} + 7x - 12 \\ = 14x$