x/45=16/40=24/x
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Consider the first two ratios [ ]/45 = 16/40 Let us assume the missing number be P Then, P/45 = 16/40 By cross multiplication we get, P = (16 × 45)/40 P = 720/40 P = 72/4 Divide both numerator and denominator by 4. P = 18 Therefore, [18]/45 = 16/40 Now, consider the last two ratios, 16/40 = 24/[ ] Let us assume the missing number be Q, Then, 16/40 = 24/Q By cross multiplication we get, Q = (24 × 40)/16 Q = 960/16 Divide both numerator and denominator by 16. Q = 60 Therefore, 16/40 = 24/[60]
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