(x-5) (x+3) = (x-7) (x+4)
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Answer:
Answer
(x−5)(x−7)(x+6)(x+4)=504{(x−5)(x+4)}{(x−7)(x+6)}=504(x2−x−20)(x2−x−42)=504
Put x2−x=t
(t−20)(t−42)=504t2−62t+840=504t2−62t+336=0t2−6t−56t+336=0t(t−6)−56(t−6)=0(t−56)(t−6)=0t=56,6x2−x=t
For t=56
x2−x=56x2−x−56=0x2−8x+7x−56=0x(x−8)+7(x−8)=0(x+7)(x−8)=
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(x−5)(x−7)(x+6)(x+4)=504{(x−5)(x+4)}{(x−7)(x+6)}=504(x2−x−20)(x2−x−42)=504
Put x2−x=t
(t−20)(t−42)=504t2−62t+840=504t2−62t+336=0t2−6t−56t+336=0t(t−6)−56(t−6)=0(t−56)(t−6)=0t=56,6x2−x=t
For t=56
x2−x=56x2−x−56=0x2−8x+7x−56=0x(x−8)+7(x−8)=0(x+7)(x−8)=0
Put x2−x=t
(t−20)(t−42)=504t2−62t+840=504t2−62t+336=0t2−6t−56t+336=0t(t−6)−56(t−6)=0(t−56)(t−6)=0t=56,6x2−x=t
For t=56
x2−x=56x2−x−56=0x2−8x+7x−56=0x(x−8)+7(x−8)=0(x+7)(x−8)=0
i have got the answer already by someone
but thanks for helping ne
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Answered by
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Answer:
-13
Step-by-step explanation:
x^2 +3x-5x-15=x^2+4x-7x-28
x^2-2x-15=x^2-3x-28
x^2 and x^2 will get canceled
-2x+3x=-28+15
x=-13
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